Hello Aspirants
Welcome to Online Quants Test in AffairsCloud.com. We are starting Cumulus Course for IBPS Clerk 2018 Main Exam and we are creating sample questions in Quants section, this type of Question will be asked in IBPS Clerk 2018!!!
Click Here to View Cumulus Course: IBPS Clerk 2018 Mains
IBPS Clerk 2018 Mains: GA Test – 7.00 PM Every Day
IBPS Clerk 2018 Mains: Reasoning Test – 8.00 PM Every Day
IBPS Clerk 2018 Mains: Quants Test – 9.00 PM Every Day
IBPS Clerk 2018 Mains: English Test – 10.00 PM Every Day
Help: Share Our Cumulus Course for IBPS Clerk 2018 Exam Course page to your Friends & FB Groups
________________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (15) Study the following table carefully answer the questions that follow :
Total number of Students – 35000
What is the ratio of the total number of males in Class VIII & Class XI together to the total number of females in Class IX & Class X together?
Correct
Answer – 2) 25:16
Explanation:
Required ratio = {(30 *40)+ (15 * 45)}/{(10 *30) + (20 *45)}=25:16Incorrect
Answer – 2) 25:16
Explanation:
Required ratio = {(30 *40)+ (15 * 45)}/{(10 *30) + (20 *45)}=25:16 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (15) Study the following table carefully answer the questions that follow :
Total number of Students – 35000
If 35% of males in Class XII & 46% of females in Class XII want to leave the class, then what is the approximate total number of students who want to leave?
Correct
Answer – 1) 3448
Explanation:
Required number =35000 *25/100 (60 % *35% + 40 % of 46 %)=3447.5Incorrect
Answer – 1) 3448
Explanation:
Required number =35000 *25/100 (60 % *35% + 40 % of 46 %)=3447.5 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (15) Study the following table carefully answer the questions that follow :
Total number of Students – 35000
What is the difference between the number of females in Class VIII & Class X together & the number of males in Class IX & Class XII together?
Correct
Answer – 3) 1750
Explanation:
Required Difference
= {(20/100*45/100+30/100*60/100)(10/100*70/100 +25/100 *60/100)} =1750Incorrect
Answer – 3) 1750
Explanation:
Required Difference
= {(20/100*45/100+30/100*60/100)(10/100*70/100 +25/100 *60/100)} =1750 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (15) Study the following table carefully answer the questions that follow :
Total number of Students – 35000
The total number of students in Class X is what percent of the total number of students in Class VIII & Class XI together?
Correct
Answer – 2) 400/9%
Explanation:
Required %= (20 *100)/(30+15)=400/9%Incorrect
Answer – 2) 400/9%
Explanation:
Required %= (20 *100)/(30+15)=400/9% 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (15) Study the following table carefully answer the questions that follow :
Total number of Students – 35000
If 25% females in Class XI want to be Engineer & 15% want to be Doctor while 20% of males in Class XI want to be Engineer & 25% want to be Doctor then approximately what is the total number of students who want to be Engineer & Doctors together?
Correct
Answer – 2) 2219
Explanation:
Required = 35000{(25+15)% of 55% of 15% + (20 +25)% of 45% of 15%}
2218.125 = 2219(approx)Incorrect
Answer – 2) 2219
Explanation:
Required = 35000{(25+15)% of 55% of 15% + (20 +25)% of 45% of 15%}
2218.125 = 2219(approx) 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe ratio of efficiency of Sharma to Pramod is 5:3. The ratio of number of days taken by Rishi to Pramod is 2:3. Sharma takes 6 days less than Pramod, when Sharma and Pramod complete the work individually. Rishi and Pramod started the work and left after 2 days. The number of days taken by Sharma to finish the remaining work is?
Correct
Answer – 3) 6 days
Explanation :
Ratio of number of days = 9:10:15
Work done By Rishi and Pramod in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 daysIncorrect
Answer – 3) 6 days
Explanation :
Ratio of number of days = 9:10:15
Work done By Rishi and Pramod in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 days 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA watercraft running upstream takes 8 hours 45 minutes to cover a certain distance, while it takes 5 hours to cover the same distance running downstream. What is the ratio between the speed of the watercraft and speed of the stream respectively?
Correct
Answer – 2) 11 : 3
Explanation :
x*35/4 = 5y
y = 7x/4
Required Ratio = (Y + X / 2) : (Y – X / 2)
11x/8 : 3x/8 = 11:3Incorrect
Answer – 2) 11 : 3
Explanation :
x*35/4 = 5y
y = 7x/4
Required Ratio = (Y + X / 2) : (Y – X / 2)
11x/8 : 3x/8 = 11:3 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA circular garden is surrounded by a concrete wall 4 feet wide. If the area of the concrete wall surrounding the garden is 11/25 that of the garden, then the radius of the garden is?
Correct
Answer – 2) 20ft
Explanation :
Radius of the garden = x
Radius of the garden including the wall = x+4
Area of the concrete wall = Π[(x+4)^2 – x^2] =8Π(x+2)
8Π(x+2) = 11/25Πx^2
X = 20 feetIncorrect
Answer – 2) 20ft
Explanation :
Radius of the garden = x
Radius of the garden including the wall = x+4
Area of the concrete wall = Π[(x+4)^2 – x^2] =8Π(x+2)
8Π(x+2) = 11/25Πx^2
X = 20 feet 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative Aptitude3, 5, 8, 26, 88, 345
Correct
Answer – 3) 26
Explanation :
3 + 1² + 1 = 5
5 + 2² – 1 = 8
8 + 4² + 1 = 25
25 + 8² – 1 = 88
88 + 16² + 1 = 345Incorrect
Answer – 3) 26
Explanation :
3 + 1² + 1 = 5
5 + 2² – 1 = 8
8 + 4² + 1 = 25
25 + 8² – 1 = 88
88 + 16² + 1 = 345 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeSharma started travelling from a place M to N and Pranav started travelling from a place N to M which are 672 km apart. They meet after 14 hours. After their meeting, Sharma increased her speed by 2 kmph and Pranav reduced her speed by 2 kmph, they arrived at N and M respectively at the same time. What is their initial speed?
Correct
Answer – 3) 25 kmph, 23 kmph
Explanation :
Sum of their speeds = Distance/time = 672/14 = 48 kmph
Respective Speed of Sharma and Pranav = (25 + 23) = 48 kmphIncorrect
Answer – 3) 25 kmph, 23 kmph
Explanation :
Sum of their speeds = Distance/time = 672/14 = 48 kmph
Respective Speed of Sharma and Pranav = (25 + 23) = 48 kmph
________________________
 Click view Questions button to view Explanation
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 If you find any mistake, please tell us in the comment section.s